Zigzag Conversion
The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
1
string convert(string s, int numRows);
Example 1:
- Input: s = “PAYPALISHIRING”, numRows = 3
- Output: “PAHNAPLSIIGYIR”
Example 2:
- Input: s = “PAYPALISHIRING”, numRows = 4
- Output: “PINALSIGYAHRPI”
- Explanation: P I N A L S I G Y A H R P I
Example 3:
- Input: s = “A”, numRows = 1
- Output: “A”
Constrains:
1 <= s.length <= 1000
s
consists of English letters (lower-case and upper-case),','
and'.'
.1 <= numRows <= 1000
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
#include <vector>
#include <string>
using namespace std;
class Solution {
public:
string convert(string s, int numRows) {
// If numRows is 1 or less than or equal to the length of s, return s as is
if (numRows == 1 || numRows >= s.length()) {
return s;
}
// Initialize an array of strings to store characters for each row
vector<string> rows(min(numRows, int(s.length())));
int curRow = 0;
bool goingDown = false;
// Iterate through each character in the string and append it to the appropriate row
for (char c : s) {
rows[curRow] += c;
// Change direction when reaching the first or the last row
if (curRow == 0 || curRow == numRows - 1) goingDown = !goingDown;
curRow += goingDown ? 1 : -1;
}
// Combine characters from all rows into a single string
string ret;
for (string row : rows) ret += row;
return ret;
}
};
This post is licensed under CC BY 4.0 by the author.